Wednesday, December 19, 2007
See ya
Tuesday, December 18, 2007
Monday, December 17, 2007
December 17, 2007
Thursday, December 13, 2007
December 13 2007
Today we started the class off with mental math. After mental math we dicussed and went over the Bob and Carol question using the Statement of Net Worth spread sheet found in our applied math folder. Their total liabilities is $133,500, the net worth $115,500and the debt equity ratio is 29.00433. If Bob and Carol are in their 20's or 30's they are doing very well and if they are in their 50's or 60's then they would be doing not so well. We got a definition of liquidity which is the relative ease of converson to cash without loss of principal. We were assigned 2 questions from the personal finance review booklet ( #3 Maila and #6 Ralph ) they are both due for Monday. Use TVM solver or Excel. Tommorrow Mr. Max wont be here so you can work on these questions or work on the old exams for practice.
December 12 2007
We then took some notes on debt equity ratio. The notes got deleted so I cant really put them on here. The formula for debt equity ratio is....
total liabilities-mortgage on principal ratio divided by net worth.
Our homework was to find out Bob and Carols D.E.R.
Tuesday, December 11, 2007
Dec. 10
Tuesday, December 11
Mr. Max was really impressed with our efforts from yesterday on the blog. Other then a few constructive criticisms, he said over all he was impressed. Many people have to correct their grammar, everyone talks like they are texting, or on facebook. This is a very bad habit that people need to break before going on to post secondary education. We are losing our vocabulary by trying to use the fastest way to say something, without doing it properly. It is not just this class, it is people all over the world.
We did some personal finance questions on the Written Test of January 2006
Page 14, Question 13
Amortized
Amortize(v.) Total length of time that it takes to repay a loan
Amortization(n)

Homework for tomorrow is Question 14 on the Written TestJanuary 2006, Page 15
Monday, December 10, 2007
Solution to #8
Day 1: Take pill # 1: 500 mg
Day 2: 500*.75= 375 mg
Take pill #2: 375+500= 875 mg
Day 3: 875*.75= 656.25 mg
Take pill #3: 656.25+500= 1156.25 mg
Day 4: 1156.25*.75= 867.19mg
Take pill #4: 867.19+500= 1367.19 mg
Day 5: 1367.19*.75= 1025.39 mg
Take pill #5: 1025.39+500= 1525.39 mg
Day 6: 1525.39*.75= 1144.04mg
Take pill #6: 1144.04+500= 1644.04mg
Part b)
Day 1: Take two pills: 1000 mg
Day 2: 1000*.75= 750 mg
Take two pills: 750+1000= 1750 mg
Day 3: 1750*.75= 1312.5 mg
Take half a pill: 1312.5+250= 1562.5 mg
Day 4: 1562.5*.75= 1171.875 mg
Take half a pill: 1171.875+250= 1421.875 mg
Day 5: 1421.875*.75= 1066.41 mg
Take half a pill: 1066.41+250= 1316.41 mg
Day 6: 1316.41*.75= 987.3075 mg
Take half a pill: 987.3075+250= 1237.3075 mg
antibiotics
day 2- 875
day 3- 1156.25
day 4- 1367.1875
day 5- 1525.390625
day 6- 1644.042969
B)
First day- 2 pills = 1000 mg
second day- 1 pill = 1250 mg
third day- 1 pill = 1437.5 mg
fourth day- 1 pill = 1578.125 mg
fifth day- 1 pill = 1683.59375 mg
this solution works because it say for more than 5 days so if you they were picky and checked on the sixth day the level of antibiotics would still be 1262.695313 mg even tho you dont take a pill on the sixth day.
answers to the medication question
Day 2: 875mg
Day 3:11560.25
Day 4:1367.1875 mg
Day 5:1525.39 mg
Day 6:1644.04 mg
b)Day 1: take 2 500 mg pills= 1000 mg
Day 2: 75% of medication left= 750mg then take half a pill which=250 mg then it adds up to 1000mg. Just keep taking half a pill everyday and you should have 1000 mg of the medication daily. After 6 days there will still be 2 pills left so the medication will last 9 days.
antibotic question
Antibiotic Question
Day 2 - 875mg
Day 3 - 1156.25mg
Day 4 - 1367.19mg
Day 5 - 1525.39mg
Day 6 - 1644.04mg
B)On the first day you could take two pills to give you 1000mg on the first and then a half of a pill for every day for at least five more days.
#8 homework
1st day --> 500mg 125
2nd day--> 875mg [500+(500-125)] 218.75
3rd day --> 1156.25 mg [500+(875-218.75)] 289.06
4th day --> 1367.19mg [500+(1156.25-289.06)] 341.8
5th day --> 1525.39mg [500+(1367.19-341.8)] 381.35
6th day --> 1644.04mg [500+(1525.39-381.35)]
*The green represents the amount released from the previous day, and the blue is the amount released from the corresponding day.
b) To achieve a level of at least 1000mg daily using only 6 pills, take 2 pills (500mg each) the first day and then half a pill (250mg each) each morning until all six pills run out. This is the work:
1st day --> 2 pills x 500mg each = 1000mg
2nd day --> [250+(1000-250)] = 1000mg
*in the square brackets the first 250 represents the amount of mg in half a pill, the information in the round brackets represents the amount of mg lost from the first day.
3rd day --> [250+(1000-250)] = 1000mg
4th day --> [250+(1000-250)] = 1000mg
5th day --> [250+(1000-250)] = 1000mg
This only used 4.5 pills, but the level of at least 1000mg was reached.
caitlynd and cindy
YAY Homework
For A I thought that you only take the 25% of of the pill that you take for the day and not take 25% off of everything that you have in your body from the days before to. So for my answer i got 2250 mg of antibiotic in the body after the sixth day. If you took 25% of of everything that you have in your body that day then your answer will be different.
For B I took 2 pills the first day and then I took only a half a pill a day for the next 5 days to maintain the 1000 mg a day need. This question is like the other so if you take 25% off of the full amount in your body your answer may very instead of taking 25% of off of just the pill you take that day.
drug question
For b) i followed pretty much the same pattern as a). I started out with two pills on day one to acquire the 1000mg needed. I then took 1/2 a pill per day until day 9 which gave me my six pills and exacly 1000mg of drugs in the body each day.
#8 Pills
day 2____ 875mg
day 3____1156.25mg
day 4____1367.19mg
day 5____1525.39mg
day 6____1644.04mg
B) You could take 2 pills the first day. On the second day you could take 1 pill. The third day you could take 1. The forth day you could take your last 2 pills.
Infections and Antibiotics
term starts 8:am each morning
by next day 25% of antibitoic is consumed.
a) 500*.75= amount left over at 8:am next morning
day1= 500
day2= 375
day3=381.25
day4=158.20
day5=118.65
day6=88.99
b) 1000mg of antibiotic per day. within the rules of pills can only be taken at 8:am and no partial pills are needed.
day1= 2x500mg
day2= 2x500mg
day3= 1x500mg
day4= 1x500mg
day5= 1x500mg
day6= 1x500mg
taking in total 8 pills of 500mg will not allow the body's antibotic level to fall below 1000mg. over the six days you would have consumed in total 4000mg of antibiotics.
jason
Antibiotic Question....... #8
Day _Amount _Equations
1 ___500______500
2___875 ___500 + 500- 125(.25)
3 __1156.25 __500 + 875 - 218.75(.25)
4__ 1367.19___500 + 1156.25-289.06(.25)
5 __1525.39 __500 + 1367.19-341.80(.25)
6 __1644.04___ 500 + 1525.34-381.35(.25)
(.25) just shows that it is 25% of that number
b)
Day Amount
1__ (.25) 1000 = 250
2 __250 + (1000 - 250)
3 __250 + (1000 - 250)
4 __250 + (1000 - 250)
5__ 250 + (1000 - 250)
6 __250 + (1000 - 250)
Amount to take: ,
1 = 1000 mg
2 = 250 mg
3 = 250 mg 1000 mg.
4 = 250 mg
5 = 250 mg
6 = 250 mg
Answer: Take 2 pills the first day, then take 1/2 a pill for the remainder of the days to obtain your 1000 mg
Question 8 Home Work Check
2- 875mg
3- 1156.25
4- 1367.19
5- 1525.39
6- 1644.04
B) 1 and 1/2 pills for 4 days = 6 pills
Day 1 - 750mg
2 - 1312.50mg
3 - 1734.37mg
4 - 1863.28mg
5 - 1397.46mg
6 - 1048.08mg
7 - 786.1mg
Question #8
Days /Equations/amounts per day
1st day -- 500mg
2nd day -- (500+(500-125))= 875mg
3rd day -- (500+(875-218.75))= 1156.25mg
4th day -- (500+(1156.25+289.06))= 1367.19mg
5th day -- (500+(1367.19-341.80))= 1525.39mg
6th day -- (500+(1525.34-381.35))= 1644.04mg
b)
Day /Equations /Amount to take
1 -- 0.25(1000)= 250 1000mg
2 -- (250+(1000-250)) 250mg
3 -- (250+(1000-250)) 250mg
4 -- (250+(1000-250)) 250mg
5 -- (250+(1000-250)) 250mg
You should take 2 pills the first day and then 1/2 of a pill each of the following days.
500*.75=375mg-->Day 1
375*.75=281mg-->Day 2
281*.75=211mg-->Day 3
211*.75=158mg-->Day 4
158*.75=119mg-->Day 5
119*.75=89mg-->Day 6
8b) Day 1--> take 2 pills (375*2=750)
Day 2--> take half a pill (281/2=141)
Day 3--> take half a pill (281/2=141)
Day 4--> take half a pill (281/2=141)
Day 5--> take half a pill (281/2=141)
=(141*4) + 750
=1314mg
(By taking 4 pills in a period of 5 days)
Question #8
a) 1st day: 500mg - 375mg - 250mg - 125mg - 0mg
2nd day: 500mg - 375mg - 250mg - 125mg - 0mg
3rd day: 500mg - 375mg - 250mg - 125mg
4th day: 500mg - 375mg - 250mg
5th day: 500mg - 375mg
6th day: 500mg
* Add all the bold numbers to get the total amount of medication
Total = 1250mg (125 + 250 + 375 + 500)
* You loose 25% each day (125mg) so there would not be any left from day 1 abd 2 because that would be 5 and 6 days. The pills only last 4 days. So therefore you only count day 3, 4, 5, and 6.
b) 1st day: 2 pills (1000mg)
2nd day: 1/2 pill (250) 750mg left from last day (750 + 250 = 1000mg)
3rd day: 1/2 pill (250) 750mg left from last day (750 + 250 = 1000mg)
4th day: 1/2 pill " "
5th day: 1/2 pill " "
Total amount of pills = 6 (bold numbers)
She would take 2 pills the first day and then take a half of a pill each day after that, to maintain a 1000mg of medication.
Friday, December 7, 2007
Fractals
Last day of Sequences... Today Mr.Max is going over the homework. Questions 6 and 10.
6.


homework for the weekend - question 8 and finish question 14 too.
Alsoooo Mr.Max handed us out Applied Mathematics Standards tests for us to look at. Very nice of him to do that. They willl be very useful to us i think.
Thursday, December 6, 2007
So we started off the class with mental math. He then went around the room and did a homework check on question 15 on our Sequence review package (Murky Island bears).
If you don't have excel on your computer at home Mr, Max recommended using.......google docs and spreadsheets (docs.google.com)



http://www.coolmath.com/fractals/fractals_lesson.html
I don't know if this website will help you any but it looks like Mr. Max created it even the writing looks the same!
Wednesday, December 5, 2007
Sequences and Series
In October, an oil well in Alberta produced 80m³ of oil. Each month, the well produces 3.1% less oil than the previous month.
a) In total, how much oil will be produced during a 6-month period beginning October 1st.

Method #1 (home screen method)
· Add all 6 months = 444.31m³
b)Once the well production drops below 60m³ per month, it is not profitable to operate the well. In which month will it no longer be profitable to operate the well?
Continue pressing enter to get the following numbers:
a) Method #2 – Sequence Mode on the Calculator
Mode - seq – Y=
2nd 7 = funny looking u
(n-1) press X,T,θ,n to get italicized n
*“The u(n) term in the sequence is dependent on the u(n-1) term”
Window Change settings depending on question.
Ymax- is greater than 80 because 80 is the most oil we are going to have.
Graph Line graph is shown, trace trace to find the number you want. In this question we want to go 10.
b)Gather numbers together and add them together to find b.
Method #3- Excel – make a spreadsheet

Method #4 – Shodor Websote “Sequencer interactivity

*you may use this website (as you did Ron Blond), provided you indicate all inputs.
http://www.shodor.org/interactive/activities/Sequencer
Hopefully this is a litte bit easier to read, personally I find the notes off the smart board hard to read on the blog so I figured I would try it this way.
Jayde
Monday, December 3, 2007
The answer for method one without PST and GST 8932.00 and the second method is 11381.72.